Valid Anagram

In this task, I worked on checking whether two given strings are anagrams of each other. Anagrams are words that contain the same characters but arranged in a different order. What I Did I created a function isAnagram that takes two strings as input and returns True if they are anagrams, otherwise False. For example: Input: s = "listen", t = "silent" Output: True How I Solved It First, I checked if both strings have the same length. If they don’t, they cannot be anagrams. Then I used a dictionary to count how many times each character appears in the first string. After that, I went through the second string: If a character is not in the dictionary or its count is already zero, I return False Otherwise, I decrease the count for that character Code class Solution: def isAnagram(self, s: str, t: str) -> bool: if len(s) != len(t): return False count = {} for c in s: count[c] = count.get(c, 0) + 1 for c in t: if c not in count or count[c] == 0: return False count[c] -= 1 return True How